Identify the horizontal asymptote of f(x)= 4x/7

6 years agoare you sure you have question right?

6 years agoone moment i'll draw it :)

6 years ago|dw:1345224680095:dw|

6 years agothis equation represents a straight line through the origin

6 years agowell here are the choices..

6 years agoy=4/7 y=0 y=7/4 no horizontal asytope

6 years agosoo...it's no horizontal?

6 years agoyes

6 years agojust making sure thank you very much.

6 years agoyw

6 years agoand thank you cuzzin for last time :)

6 years agoYes, no horizontal. For a horizontal asymptote to occur, either (1) the degree of the numerator is less than that of the denominator (in which case, HA is y=0), or (2) the degrees in the numerator and denominator are equal, in which case you would divinde the leading coefficient in the numerator by the leading coefficient in the denominator. This will give you your HA.

6 years agoNo prob

6 years agoyou guys are life savers.. thank you so much

6 years ago