Identify the horizontal asymptote of f(x)= 4x/7

Question

cwrw238 · Answer

are you sure you have question right?

rayford · Answer

one moment i'll draw it :)

rayford · Answer

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cwrw238 · Answer

this equation represents a straight line through the origin

rayford · Answer

well here are the choices..

rayford · Answer

y=4/7

y=0

y=7/4

no horizontal asytope

rayford · Answer

soo...it's no horizontal?

cwrw238 · Answer

yes

rayford · Answer

just making sure thank you very much.

cwrw238 · Answer

yw

rayford · Answer

and thank you cuzzin for last time :)

anonymous · Answer

Yes, no horizontal. For a horizontal asymptote to occur, either (1) the degree of the numerator is less than that of the denominator (in which case, HA is y=0), or (2) the degrees in the numerator and denominator are equal, in which case you would divinde the leading coefficient in the numerator by the leading coefficient in the denominator. This will give you your HA.

anonymous · Answer

No prob

rayford · Answer

you guys are life savers.. thank you so much