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Mathematics 39 Online
OpenStudy (anonymous):

Can anyone tell me the height of this? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0810_19/image0034e68d166.jpg

OpenStudy (anonymous):

It isn't 8 cm?

OpenStudy (anonymous):

Well it states in the whole question that the diameter is 8. I didn't think that I should use it for the height too?

OpenStudy (anonymous):

Oh ok. No those are different.

OpenStudy (anonymous):

Maybe 12+5... Why else would those be there. See I'm trying to find the surface area of this whole figure.

OpenStudy (anonymous):

no not that

OpenStudy (anonymous):

height will be \[12 + 2*(\sqrt{5^{2}-4^{2}})\]

OpenStudy (anonymous):

Why so?

OpenStudy (anonymous):

12 is the length of the rectangle. there are 2 similar triangles on either side of it. now if you drop a perpendicular bisector on both the sides(of 8cm)from the tips of the triangle and apply Pythagoras theorem you will get the length of the perpendicular bisector as \[\sqrt{5^{2}-4^{2}}\]

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