Question

What is the product of m^2-m-6/8p * 2p/2m+m^2?
a: m+3/4m
b: m-3/4m
c: m+3/4m

Answer 1

Can you factorize it?
\[m^2 - m - 6\]

Answer 2

@waterineyes i don't know

Answer 3

Then I think you should reply fast if you don't know..

Answer 4

@waterineyes i had to do something

Answer 5

\[m^2 -m - 6\]

Here find two factors of 6 such that their product is -6 and their sum is -1:

-3 and 2..


-3*2 = -6
-3 + 2 = -1
Both condition satisfy:

So:

-3 and 2 are the factors:

Now:

\[m^2 -3m + 2m - 6 \implies m(m-3) + 2(m-3) \implies (m-3)(m+2)\]

Answer 6

What can you factor out of : \(2m + m^2\) ??

Answer 7

@waterineyes i still do not know !

Answer 8

What you don't know ??

Answer 9

@waterineyes what you can factor !!

Answer 10

what grade are you in?

Answer 11

In 2m and \(m^2\) what is common ??

Answer 12

(psst. its the m)

Answer 13

m @waterineyes

Answer 14

So by factor out it means taking m common or outside like:

\[m^2 + 2m\]
\[m(m+2)\]

This is called taking a factor out..

Answer 15

@waterineyes okk ..

Answer 16

So now your question has become:

\[\frac{(m-3)(m+2)}{8p} \times \frac{2p}{m(m+2)}\]

Now your job is to cancel out the things which are same in numerator and denominator..

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