What is the product of m^2-m-6/8p * 2p/2m+m^2?
a: m+3/4m
b: m-3/4m
c: m+3/4m
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OpenStudy (anonymous):
Can you factorize it?
\[m^2 - m - 6\]
OpenStudy (keana):
@waterineyes i don't know
OpenStudy (anonymous):
Then I think you should reply fast if you don't know..
OpenStudy (keana):
@waterineyes i had to do something
OpenStudy (anonymous):
\[m^2 -m - 6\]
Here find two factors of 6 such that their product is -6 and their sum is -1:
-3 and 2..
-3*2 = -6
-3 + 2 = -1
Both condition satisfy:
So:
-3 and 2 are the factors:
Now:
\[m^2 -3m + 2m - 6 \implies m(m-3) + 2(m-3) \implies (m-3)(m+2)\]
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OpenStudy (anonymous):
What can you factor out of : \(2m + m^2\) ??
OpenStudy (keana):
@waterineyes i still do not know !
OpenStudy (anonymous):
What you don't know ??
OpenStudy (keana):
@waterineyes what you can factor !!
OpenStudy (anonymous):
what grade are you in?
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OpenStudy (anonymous):
In 2m and \(m^2\) what is common ??
OpenStudy (anonymous):
(psst. its the m)
OpenStudy (keana):
m @waterineyes
OpenStudy (anonymous):
So by factor out it means taking m common or outside like:
\[m^2 + 2m\]
\[m(m+2)\]
This is called taking a factor out..
OpenStudy (keana):
@waterineyes okk ..
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OpenStudy (anonymous):
So now your question has become:
\[\frac{(m-3)(m+2)}{8p} \times \frac{2p}{m(m+2)}\]
Now your job is to cancel out the things which are same in numerator and denominator..