OpenStudy (anonymous):

For y = x2 + 4x − 12, Determine if the parabola opens up or down. State if the vertex will be a maximum or minimum. Find the vertex. Find the x-intercepts. Describe the graph of the equation.

5 years ago
OpenStudy (anonymous):

the parabola opens up because its positive the vertex will be minimum (thats all i have)

5 years ago
OpenStudy (anonymous):

for the x intercept just put y=0 and solve the quadratic equation

5 years ago
OpenStudy (anonymous):

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5 years ago
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