Question

If y is a negative integer, which of the following has the least value?

cube root of y^2

100^y

π/y

1/y^2

1/y^3

Answer 1

it would be a lot easier if you let y be a number..let's say -1

so y = -1
\[\large \sqrt[3]{y^2} \implies \sqrt[3]{(-1)^2} \implies \sqrt[3]{1} \implies 1\]
\[\large 100^y \implies 100^{-1} \implies \frac{1}{100}\]
\[\large \frac{\pi}{y} \implies \frac{\pi}{-1} \implies -\pi\]
\[\large \frac{1}{y^2} \implies \frac{1}{(-1)^2} \implies \frac 11 \implies 1\]
\[\large \frac{1}{y^3 }\implies \frac{1}{(-1)^3} \implies \frac{1}{-1} \implies -1\]
so which do you think is the smallest one?

Answer 2

the 2nd one