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Choose the equation of the line passing through the point (-3, -1) and perpendicular to y = 1/2x + 3.
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the slope of \(y=\frac{1}{2}x+3\) is \(\frac{1}{2}\) therefore the slope of a perpendicular line will be \(-2\)
your job now is to use the "point - slope" formula \[y-y_1=m(x-x_1)\] with \[m=-2,x_1=-3,y_1=-1\]urmssmossymmh
y = -2x - 7 ?
i don't know i didn't do it. let me check
looks good to me
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