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let g(X) = abs(cosx-1) the maximum value attained by g on the closed interval [0, 2pi] is for x equal to a. -1 b. 0 c. pi/2 d. 2 e. pi
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It is 2. for x=pi... cos x -1 = -2... so abs (Cos x -2) = 2
d. 2
how do you know?
@muah 143 didn't you see my explanation for the answer?
yeah i did...i was actually trying to see RyanL. point of view
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for any real number \[-1\le\cos x \le1\]\[-2\le\cos x -1\le0\]\[0\le|\cos x -1|\le2\]
ohhh thanks
yw :)
:)
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