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\[A=\left[\begin{matrix}1 & 0 \\ 3& 2\end{matrix}\right], B=\left[\begin{matrix}x & 0 \\ 1 & 3\end{matrix}\right]\] and AB=BA find x.
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Can you multiply out A*B?
yes
what do you get?
\[\left[\begin{matrix}x & 0 \\ 3x+2 & 6\end{matrix}\right]\]
most excellent. now do B*A
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\[\left[\begin{matrix}x & 0 \\ 10 & 6\end{matrix}\right]\]
now the problem says those two matrices are equal (corresponding elements are equal) x=x yes 0= 0 yes 6=6 yes 3x+2=10 this one is interesting. solve for x
i see.
uber cool
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