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If x≠2, and x≠-2, then what does (x^3+3x^2-10x)/(2x^2-8) equal?
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can u factorise the cubic expression in the numerator?
x(x+5)(x-2)
yes and denominator?
2(x^2-4)
which is? use a^2-b^2=(a+b)(a-b)
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if x≠2, and x≠-2
i dont get this part
since x not =2 --->(x-2) not=0 only then u can cancel out (x-2) from numerator and denominator
x(x+5)/2(x^2-4)
and x≠-2
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to cancel out x-2 from denominator,first factor the denominator as 2(x^2-4) as 2(x+2)(x-2) what is true for x-2,also applies to x+2
so it's x(x+5)/2(x+2)
yup it is :)
thanx man!
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