Question

method of substitution 3a=5-b and 3a=2-b

Answer 1

i think that's just a wrong question, dude

Answer 2

use the method of substitution to solve the system of liner equations. 3a=5-b and 3a=2-b

Answer 3

\[\large{3a=5-b\space ; 3a=2-b}\]
\[\large{\color{red}{5-b=2-b}}\]
\[\large{5-2=-b+b}\]
\[\large{\color{blue}{3\ne 0}}\]

hence no solutions

Answer 4

I thought you had to find the solution
for one equation first

Answer 5

what you say ok
\[\large{\color{blue}{b=5-3a}}\]
\[\large{\color{red}{3a=2-b}}\]
\[\large{\color{green}{3a=2-5+3a}}\]
\[\large{\color{orange}{3a=-3+3a}}\]
\[\large{\color{brown}{0\ne -3}}\]

no soln in this also

Answer 6

got it @urlilmami ?

Answer 7

lol @mathslover your posts really trigger epileptic shocks =))))