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n^2 - 4n - 1 = 0 Solve using the quadratic formula and simplify
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\[\large n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] \[\Large \implies n = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(1)(-1)}}{2(1)}\] does that help?
Yes, thank you. I was struggling with these.
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