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an isoceles triangle has a base of length 2√3 m and sides of length 2 m.Determine the exact value of the apex angle, in radians
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Start by dividing it into 2 right triangles with a line starting from the tip.
geometry or trig? @Sukhvir
trig
If you divide it into 2 right triangles, then you get a halved angle and a halved base. You can then get the angle via arcsin, then double the angle.
|dw:1345413425090:dw| now use law of cosine... \[(2\sqrt{3})^{2}=2^{2}+2^{2}-2(2)(2)\cos(\theta)\]
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