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\[\lim_{x \rightarrow -2^+} (x+3) \frac{ \left| x+2 \right| }{x+2 }\]
I do not understand well how to take the module
PTBR: não estou entendendo bem como resolver a questão do módulo
for x->-2+ mod (x+2)=x+2 so that u can cancel out x+2 in numerator and denominator
u got it @DeleonBRRJ
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perfect the result is 1
yes it is...because when u substitute x=-2 in x+3,u get 1
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