Question

simplify
(4b)^-3

Answer 1

hint: \[\Large (4b)^{-3} \implies \frac{1}{(4b)^3}\]

Answer 2

Similar Problem:


\[\Large (2z)^{-3} = \frac{1}{(2z)^3}\]


\[\Large (2z)^{-3} = \frac{1}{2^3*z^3}\]


\[\Large (2z)^{-3} = \frac{1}{8z^3}\]

Answer 3

ok so 1 over 64b^3

Answer 4

yup

Answer 5

thanks

Answer 6

welcome