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The sum of 3 numbers is 79. The second number is 9 times the first and the third number is three more than the second. Find the numbers
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Hint: x = 1st number 9x = 2nd number 9x + 3 = 3rd number x + 9x + (9x + 3) = 79
Solve for x
Thanks!
You're not done until you solve for x
Do you know how to do that?
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I simplified and did \[10x +\left( 9x + 3 \right) = 79\]Now I'm kinda confused
@Hero
Hint: Remove the parentheses and continue solving.
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