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let sin4theta=1/2 and tan4theta>0, find cos2theta
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\[\sin 4\theta = \sin \Pi/6\]
\[\theta=\Pi/24\]
book says \[1/2\sqrt{2+\sqrt{3}}\]
lol sorry misunderstanding..
we are looking for cos2(theta)
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wait...lol
ok :)
\[\cos2\theta = 1-2\sin^2\]
use this
@Yahoo! \(\theta\) is only \(\large\frac{\pi}{24}\) and not \(\sin \theta\)
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thank you :)
oh..sorryyy
\[\sin \Pi/24\]
yw...
it's k.:)
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