Question

Factor each trinomial below. Please show your work and check your answer. (1 point each)
1.x2 – 8x + 15
2.a2 – a – 20
3.a2 – 5a – 20
4.a2 + 12ab + 27b2
5.2a2 + 30a + 100

Answer 1

same procedure for all
you look for 2 numbers(example 1) whoseproduct is 15 and whose sum is -8=>-3,-5
x^2-5x-3x+15=x(x-5)-3(x-5)=(x-5)(x-3)

Answer 2

oh ok thanks man!

Answer 3

imma try 2

Answer 4

ok

Answer 5

5 and 4 make 20, but idk how to make it equal a variable lol

Answer 6

you want -20 not 20

Answer 7

ohhh
-5 and 4

Answer 8

good

Answer 9

so thats all i have to right? is -5 and 4
?

Answer 10

then complete factorization as i did

Answer 11

idk how to do that

Answer 12

hint to do factorization:
break the middle term such that their sum becomes the middle term & product becomes the side terms

Answer 13

now look one example

Answer 14

\[\Huge{\color{red}{x^2-8x+15}}\]\[\Huge{\color{green}{\implies{x^2-5x-3x+15}}}\]\[\Huge{\color{green}{\implies x(x-5)-3(x-5)}}\]\[\Huge{\color{green}{\implies (x-3)(x-5)}}\]

Answer 15

gt it @cedric ???
Do other example similarly like that :)

Answer 16

ok lemme try

Answer 17

sure! take ur time

Answer 18

i think that the 3rd one can't be factorized,are you sure its -5a and not -8a

Answer 19

so for the x's i use 5- and 4?

Answer 20

it depends on on the equation

Answer 21

the second one

Answer 22

ohh ! yes u r right @cedric :)

Answer 23

-5a+4a

Answer 24

s wht do u gt @cedric ??

Answer 25

so*

Answer 26

@cedric ???????????????????????????????????????????????????????????????????