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How do I solve this by completing the square: (x^2) - 7x - 3 = 0
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cube = 61
I don't get it.
is it an A B C D question
No.
OK. So to complete the square, you're going to try to make something of the form (x-a)^2, and then add a little to fix it.
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Yes, I did that with previous questions but when I tried it for this one, I got stuck.
|dw:1345469543783:dw|
x^2-7x-3=0 x^2-3x-4x-3=0 x(x-3)-4(x-3)=0 (x-3) (x-4) x=3,4 answer
The final answer is supposed to be in surd form though
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