A receptacle is in the shape of an inverted square pyramid 10 inches in height and with a 6 x 6 square base. The volume of such a pyramid is given by

(1/3)(area of the base)(height)

Suppose that the receptacle is being filled with water at the rate of .2 cubic inches per second. How fast is water rising when it is 2 inches deep?

Question

A receptacle is in the shape of an inverted square pyramid 10 inches in height and with a 6 x 6 square base. The volume of such a pyramid is given by

(1/3)(area of the base)(height)

Suppose that the receptacle is being filled with water at the rate of .2 cubic inches per second. How fast is water rising when it is 2 inches deep?

anonymous · Answer

So this is a related rates problem.  We have that:
$$\frac{dV}{dt}=.2$$ as given.

anonymous · Answer

Now we draw a picture:
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