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Mathematics 20 Online
OpenStudy (anonymous):

x^3+8

OpenStudy (anonymous):

use this identity\[a^3+b^3=(a+b)(a^2-ab+b^2)\]

OpenStudy (anonymous):

\[\large 8=(?)^3\]

OpenStudy (anonymous):

a=x and b=8??

OpenStudy (anonymous):

b=?

OpenStudy (anonymous):

note that \[8=2^3\]

OpenStudy (anonymous):

so what would the zeros be in this factor??

OpenStudy (anonymous):

according to the zero product property \[x+2=0\]or\[x^2-2x+4=0\]

OpenStudy (anonymous):

okay thanks! can you help me with this too---- x^4+x^2-12

OpenStudy (anonymous):

@magepker728 can you help please?

OpenStudy (anonymous):

@aaashish871 can you help?

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