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a0 =3,a1 =6 and an =an−1+6an−2+1,for n≥2. The n's n-1's and n-2's should be subscripts.
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but whats the question?whats to find or prove?
??? and then
\[a_n-a_{n-1}-6a_{n-2}=1\]characterestic equation\[\lambda^2-\lambda-6=0\]\(\lambda=2,-3\) now go for complementary solution and the particular solution...
here is a very usefull source for Recurrence Relations by Gilles Cazelais
lol! i think only u can answer without a question! :P
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lol
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