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Could someone help me with Rational Equations?
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\[\frac{ 1 }{ y-1 } + \frac{ 2 }{ y+1} =0\]
multiply each term by the LCD (y-1)(y+1) so y + 1 + 2(y - 1) = 0 the rest is easy
ok thanks
yw
\[\frac{ 2 }{ x-3 } - \frac{ 3 }{ x+3} = \frac{ 12 }{ x ^{2} - 9 } \]
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x^2 - 9 = (x + 3)(x - 3) so LCD is (x-3)(x+3) - proceed as above
\[\frac{ 1 }{ 6-x} + \frac{ 2 }{ x+3 } = \frac{ 5x }{ x ^{2} - 3x-18 }\]
can you factor x^2−3x−18?
ya
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