Question

i can't still get into the right solution to get the final answer...please help...
solve the simultaneous differential equation
20y' + 5x' + 15y = 0
x' + 4x + 2y' = 2
subject to the conditions of x(0)=y(0)=0
hence the answers are:
x= 1/2 - 1/5 e^-t - 3/10 e^ -6t/11
y= 1/5 e^-t - 1/5 e^-6t/11
what's the process of solving???