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Mathematics 20 Online
OpenStudy (anonymous):

i can't still get into the right solution to get the final answer...please help... solve the simultaneous differential equation 20y' + 5x' + 15y = 0 x' + 4x + 2y' = 2 subject to the conditions of x(0)=y(0)=0 hence the answers are: x= 1/2 - 1/5 e^-t - 3/10 e^ -6t/11 y= 1/5 e^-t - 1/5 e^-6t/11 what's the process of solving???

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