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arc HI = 80 degrees and arc JI = 75 degreed calculate mHKI.
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@dpaInc
hint 1 : sum of angles in a triangle = 180 hint 2 : \(\triangle\)HKI is an isosceles triangle hint 3 : inscribed angle \(\angle JHI\) = (central angle JI)/2 = 75/2 = 37.5
105?
thats right ! gw :)
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