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OpenStudy (anonymous):
how do i evaluate sec(x)tan^2(x)+sec(x)?
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OpenStudy (mimi_x3):
define: evaluate solve it or simplfy?
OpenStudy (anonymous):
simplify
OpenStudy (anonymous):
i changed everything into cos but im not sure what to do after that
OpenStudy (mimi_x3):
well you know that sec^2x - 1 =tan^2x
OpenStudy (mimi_x3):
then expand it with secx
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OpenStudy (anonymous):
oh okay thanks so much :)
OpenStudy (mimi_x3):
np..if you have any problems feel free to ask me :)
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