Question

Simplify:
1) 4x^2-3x-(x-x^2+3)
2) -15(4+3x)-8x=26-6(x-9).
3) 27-6(x-10)>-3x+26 write in set bulider notation

Answer 1

1) 4x^2 - 3x - (x - x^2 + 3)
4x^2 - 3x - x + x^2 - 3
5x^2 - 4x - 3

Answer 2

how you get 5x^2-4x-3

Answer 3

4x^2 + x^2 =(4+1)x^2 = 5x^2

Answer 4

4x^2 - 3x - x + x^2 - 3
I added 4x^2 and x^2,
5x^2

Then subtracted -3x - x
-4x

Then just the constant -3

hence 5x^2 - 4x - 3

Answer 5

Just subsitute:

is (-4)²-4(-4)-6=-6 ?
16+16-6 = -6
26 = -6

No.

But if it was 4 and not (-4) it would be:
4²-4(4)-6=16-16-6=-6

So (4,-6) would be a solution.

Answer 6

yeah that the solution to the question

Answer 7

what question does that go to