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how to factor x^3+8????????????
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just like the last one
\(a^3+b^3=(a+b)(a^2-ab+b^2)\) your job is to figure out what \(a\) and \(b\) are in this example it is pretty clear that \(a=x\) since \(a^3=x^3\) what is \(b\) ?
8
oh no, \(b^3=8\) you need \(b\)
\(x^3+8\) \[a^3+b^3\]
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b=2
got it!
so take \((a+b)(a^2-ab+b^2)\) and replace \(a\) by \(x\) and \(b\) by \(2\)
(x+2)(x^2+2x+4)
sorry (x+2)(x^2-2x+4)
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yes
is your picture a visual pun?
no
oh, thought it might be "lulu's back, in town"
haha i never thought of it that way, but i like it!
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