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cosø+sinø-sin2ø=1/2 ,0<=ø>=180 degree
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wait
sorry it's hard
sin2 theta = 2sintheta costheta
factorize
cos x + sinx - 2 sinx cosx = 1/2 sinx ( 1 - 2 cosx) = (1-2cosx)/2 sinx =1/2 x = 30 degree
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\[\cos x + \sin x - 2 \sin x \cos x = \frac{1}{2}\]\[\cos x -\frac{1}{2}+ \sin x - 2 \sin x \cos x =0\]\[\frac{1}{2}(2\cos x -1)- \sin x (2 \cos x-1) =0\]\[(2\cos x-1)(\sin x-\frac{1}{2})=0\]according to the zero product property \(\cos x =\frac{1}{2}\) it gives \(x=\frac{\pi}{3}\) or \(\sin x =\frac{1}{2}\) it gives \(x=\frac{\pi}{6},\frac{5\pi}{6}\)
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