Question

2+7tan²ø = 3.25sec²ø for 0<=ø>=2p

Answer 1

use the identity\[\sec^2 \theta=1+\tan ^2 \theta\]

Answer 2

can u solve it from here?

Answer 3

\[2+7\tan^2 \theta = 3.25(1+\tan^2 \theta)\]\[\tan^2 \theta =\frac{1}{3}\]