Question

factor the algebraic expression below in terms of a single trigonometric function.

cos x - sin 2^x - 1

Answer 1

sin^2 x-1= cos^2 x... \[-cosx- (\cos^2 x-1)-1= -\cos^2 x-\cos x=0\]

Answer 2

now solve for x

Answer 3

just consider cos x= y ...\[y^{2}-y=0...y(y-1)=0\]

Answer 4

thank you !!!!!

Answer 5

:))