Find the vertex of the parabola by completing the square. x^2-6x+8=y B. (3,-1) C. (-3,1) D.-(-1,3)
vertex of a parabola? u mean the axis of symmetry..?
No the vertex of a parabola is what it is on my test
why not u graph it on a graphic calculator? or u dont have 1..?
no i do not
just graph from -3<x<3
oh ok.. there is an easier way.. x = b/2a
that will get u ur x value for ur vertex
answer is A rite?
u want to know how i got the formula x = -b/2a?
do yu mean B because i didnt post A and yes please
umm yeah i meant B lol ok.. u see when u graph the parabola from -3<x<3 u will see that its like a U shape or u could just graph y=x^2 on a paper then the shape of the graph is like a U that cuts the x axis and y axis at (0,0)
now when u differentiate the equation.. u learn differentiation alrdy rite?
No i havent
uh oh.. then thats not good. i could give u a website it should explain well but i guess u can just memorize the formula x=-b/2a
yes.
or u can just learn the basics of differentiation on google i think u just take 10 mins to understand and u are ready to go
Alright thank you
no problem
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