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The area of a rectangle is the product of width and length. If a rectangle has length 18mthe square root of 5 times m. and width the square root of 4 times m., which of the following is the area of the rectangle?
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\[(18\sqrt5\times m)\times(\sqrt4 \times m)\] Is this the question? (As in, do the length and width look right to you?)
\[\frac{ 18m \sqrt{5m} }{ \sqrt{4m} }\]
oops you have to multipy them to find the area..
like the top and bottom
\[18m \sqrt{5m} \times \sqrt{4m}\]
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is m the meter or is m an unknown??
its just a variable i guess
\[18m \sqrt{5m} \times 2 \sqrt m\]
can you solve from here?
\[36m^2 \sqrt5\]
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\[36m \sqrt{5m^2}\] (The step before)
thank you so much :))))
you're welcome.
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