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Write an equation in slope-intercept form for the line perpendicular to y=1/2x +7 that passes through (-1,3)
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use y-y1= m(x-x1) and here m= negative inverse of the slope of given line...since required line is perpendicular to the given therefore it's (y-3)= -2(x+1)
wait quick other question sorry lol (14-a^0b^2)^-3 subsitute a=-2 and b=4 I know how to subsitute, but i'm confused about the negatives. when you subsitute the -2, is it this?|dw:1345660755996:dw| and does the 2 become -1 or 1?
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