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a charge is Q is placed at x=4m on the x-axis, and a second charge q is placed at the origin, if Q=75nC and q=8nC, what is the electric field on the y-axis at y=3m?
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B=F/q => kQ/r^2 so my r=3?
@rajathsbhat
r is differnt for the fields of the 2 charges.|dw:1345664329497:dw|
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