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questions 1 and 2 need help (attached file)
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1/y^-3 equal to y^3. try to find the answer now. it is simple
wow so quick to repost the question \[\frac{4}{y^{-3}} = \frac{4}{\frac{1}{y^3}} = \frac{4}{1}\frac{y^3}{1} = 4y^3\]
thank you..
question 2. you take the power of the numerator minus the power of the denominator
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\[\frac{a^6b^3}{a^4b^2} = a^6b^3a^{-4}b^{-2} = a^{6+(-4)}b^{3+(-2)} = a^{2}b^{1}\]
I provided all the rules for these problems in the original question posted if you don't understand something instead of re-posting the question just show your work and what I gave you wasn't advice.
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