Question

Physics dimensional analysis help?
#3 on this page: http://www.mrc.uidaho.edu/~atkinson/ECE330_EO/Summer_2009/HW/HW1Fa08_EO330.pdf

Answer 1

yeah?

Answer 2

The question is as stated above
FWIW I'm trying to switch out of Physics C into Physics B

Answer 3

there should be no math involved in this except logs ... yeah. Everything else is dimensions
but I don't know if the number of atoms has dimensions

Answer 4

what the heck are you reading?

Answer 5

... #3 man

Answer 6

m^3 * m/s^2 *m * kg/m^3
----------------------------- = should be unit less
joules/T *T

Answer 7

do you know logs yet, rym?

Answer 8

yes naturally

Answer 9

Lol... naturally. Hehe.. heh

Answer 10

So not dimensionally correct

Answer 11

Oh wait... not necessarily so if the denom and numerator cancel

Answer 12

okay, so still no

Answer 13

I don't think that's correct

Answer 14

is that equipartition of energy?

Answer 15

(m^3 *(m/s^2)*m* ((kg )/m^3))
------------------------------
j/T * T


=
1 kg m^2/s^2
----------------------
j

1 kg m/s^2 *m
----------------------
j


1 kg* acceleration *m
----------------------
j

1* newton* meter
---------------
j

newton*meter=j

j/j=1

Answer 16

lib is still on question number 1?

Answer 17

that's 3

Answer 18

@rymdenbarn

Answer 19

So it DOES cancel... it's a yes then?

Answer 20

yes

Answer 21

Thanks