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what is the trigonometric identity for ( half angle) sin^2x= EMERGENCY last thing I need to know before my test.. Please help guys.. Well appreciative
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im not allowed to open that up.. theres a lock on my computer.. can u help me shane.
The lock isn't working well if you're allowed here then :P \[sin^2 \theta=\frac{1}{2}(1=cos(2 \theta))\]
Typo in there...that should have been: \[sin^2 \theta=\frac{1}{2}(1-cos(2 \theta))\]
thanks bro
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and lol it just prevents me from opening stuff up
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