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OpenStudy (anonymous):
p=16e^0.06t what is the continuous rate?
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OpenStudy (anonymous):
is it 0.06?
OpenStudy (istim):
If you mean constant, I think it is 16. But yes, I do also think 0.06 relates to the rate.
OpenStudy (anonymous):
can someone please make sure that the continuous rate is 0.06?
OpenStudy (anonymous):
yes, it is \(.06\)
OpenStudy (anonymous):
p. 222 http://finedrafts.com/files/Larson%20PreCal%208th/Larson%20Precal%20CH3.pdf
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