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using the appropriate special triangle, 2 sqaureroot 2cosx= 2
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and the question is....?
solve for x ?
in that case x = 2n(pi) + pi/3
nono determine if 0 degrees is bigger than 90 degrees or or less
determine if 0 degrees is bigger than 90? of course 90 degrees is bigger than 0! o.O
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nono like yeah I guess solve, and find out how many degrees it is
... make up your mind plz
:D !!
I have to solve the question ... using special triangles
....so it is solve for x....?
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try this way: 2\[\sqrt{2cosx}\]=2....divide both sides by 2 u'll get \[\sqrt{2cosx}\]=1.....now square both sides u'll get 2cosx=1..............divide both sides by 2 u'll get cosx=1/2......can u figure out the rest from here?
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