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Mathematics 22 Online
OpenStudy (anonymous):

solve for x: x^3 - 2x^2 -5x +6 = 0 please show step y step

OpenStudy (anonymous):

x^3-2x^2-5x+6=0 put x=1 in equation 1-2-5+6=0 0=0 lhs = rhs hence x=1

OpenStudy (anonymous):

hint \(x=1\) is a root factor out \(x-1\) see what happens

OpenStudy (anonymous):

this is also hit and trial

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