Question

make an equation for this.. :
Two years ago,a man's age was three times the square of his son's age.In three years time, his age will be four times his son's age.Find their present ages.

Answer 1

in one or two unknowns?

Answer 2

it's given find their present ages..

Answer 3

sorry had no connection
ok
if x is the current age of the father and y that of the son then:
two years ago the father was (x-2) and the son was (y-2)
=>(x-2)=3(y-2)^2........equation 1
and
in three years the father will be (x+3) and the son (y+3)
=>(x+3)=4(y+3)....equation 2
now try to solve the system for x and y

Answer 4

isn't is possible to make an equation with one variable?

Answer 5

it is,but sounds a little weird
let x be the son's age in 3 years
his father's age will be 4x
two years ago the son was x-5 and the father was 4x-5
=>(4x-5)=3(x-5)^2

Answer 6

i made an equation like:
3(x-2)^2=4(x+3)

but it's not giving the right answer.

Answer 7

the answers should be 29 and 5

Answer 8

wow great.. it's right.. which equation you used??

Answer 9

the system in x and y is actually easier to understand
if you use my second approach you'll get the age of the son in 3 years,so you have to subtract 3 from x...

Answer 10

but i think i have to do it in single variable equation.. just tell me what's the correct equation for this?