Question

LAST PROBLEM (:

Answer 1

ABCD is an inscribed quadrilateral whose diagonals intersect at F. Segment AB is parallel to segment DC, as shown below.

Answer 2

Prove that if angle DAC is 40° and angle ACD is 35°, then angle BDA is 70°. Write a two-column proof showing statements and reasons.

Answer 3

since: angle"DBA" and "DCA" inscribed on same arc "DA" ;then: the measure of the two angles are equal ;then measure angle"DBA"=35 "first step " scince CD is parallel to BA ; then measure angle CAB" = measure angle "DCA" then measure angle CAB = 35 "second step" in the triangle DBA measure angle "DAB"=40 = 35 = 75 and measure angle"ABD"=35 ; then measure angle "BDA" =180 -(75+35)= 70 as requried