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I need help solving the following basic linear equation: 1-3y/5=2
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is 3y or (1- 3y) over 5?
\[1-3y \div5=2\]
1-3y over 5 equals 2
1-2=3y/5, -1*5=3y -5/3=y
It says the answers is -3 that is why I am confused
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I got the same thing as you the first time
(1-3y)/5=2, 1-3y=2*5 -3y=10-1, y=9/-3, y=-3
@haganmc thank you it makes sense
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