Question

factor the trinomial completly

it is y^3-14y^2+45y

Answer 1

y^3-14y^2+45y
Take out the common factor
= y ( y^2 - 14y + 45)
Split the middle term
= y ( y^2 - 5y - 9y + 45)
Take our the common factor again
= y [ y(y-5) - 9(y-5)]
Again, take out the common factor and group the rest, can you do it?

Answer 2

wait i m doing

Answer 3

y^3-14y^2+45y
Take y as common
=>y( y^2 - 14y + 45)
Then factor the quadratic equation
=>y(y^2-5y-9y+45)
=>y[ y(y-5) - 9(y-5)]
=>(y)(y-5)(y-9)

Understood @shivraj ??