Question

The length of a rectangle is 4cm more than breadth,the area of a rectangle is 96cm^2.Find the sides

(ANSWERS: 8cm and 12cm)

Answer 1

where r u stuck?

Answer 2

i did'nt understand the Q

Answer 3

\[A_{\text{rectangle}}=l\times b\]
\[l=b+4\]

Answer 4

\[A_{\text{rectangle}}=(b+4)\times b\]
\[96=b^2+4b\]
\[b^2+4b-96=0\]
\[b=\frac{-(4)\pm\sqrt{(4)^2-4\times(1)\times(-96)}}{2(1)}\]

Answer 5

you will get solutions for b , only one of them can be the breadth of a rectangle,

use this to find the length,