Question

The AM and HM of roots of a quadratic equation are 9 and 16/9 then the equation is?

Answer 1

the real form of a quadratic equation is\[\LARGE{ax^2-(\alpha + \beta)x+c}\]put the roots & solve it

Answer 2

HM = 2ab/(a+b)

AM = a+b/2

Answer 3

sorry i forgot c= alpha * beta

Answer 4

1 st find a+b

and ab

Answer 5

AM = a+b/2 = 9

a+b = 18

Answer 6

\[\LARGE{ax^2-\left( 9+{16 \over 9 }\right)+\left( 9 \times {16 \over 9} \right)}\]

Answer 7

HM = 2ab/(a+b) = 16/9

Answer 8

Find ab?

Answer 9

Then....Form a quad eq..))

Answer 10

u get ab = 16

Answer 11

nw fom...quad eq...))

Answer 12

x^2 - (a+b)x + ab =0

Answer 13

so.

x^2 - 18x + 16=0

Answer 14

\[\LARGE{ax^2-\left( 81+16 \over 9 \right)+\left( 16 \right)}\]

Answer 15

gt it @DLS ??
can u d it further ?

Answer 16

@Yahoo! thanks a lot !
@jiteshmeghwal9 your way confused me kinda sorry :/ thanks anyway! :)

Answer 17

np :)

Answer 18

thanks to both of you!

Answer 19

welcome....

Answer 20

@jiteshmeghwal9 gud..try...... u knw @DLS he is just in 8th std

Answer 21

nop..@jiteshmeghwal9 .... i said..u r in 8th......@DLS = 11 std

Answer 22

@Yahoo! am i in VIII?

Answer 23

lol

Answer 24

ohhh !

Answer 25

again mistake

Answer 26

haha

Answer 27

hm..hm....i was not knwing that.....))

Answer 28

hahaha!

Answer 29

ur question seems to be in higher level..))

Answer 30

nope i have tried these questions in my N.T.S.E. books :)
@Yahoo!

Answer 31

i think u may be IIT-Aspirant..))) like ur brother @jiteshmeghwal9

Answer 32

no ! my aim is to give CAT exam :)

Answer 33

hm.. @DLS wat is ur aim..))

Answer 34

IIT JEE 2014

Answer 35

u r in 11

Answer 36

yes

Answer 37

best of luck both of u for ur IIT-JEE :)

Answer 38

thanks!

Answer 39

thxx...

Answer 40

:)

Answer 41

http://openstudy.com/study#/updates/50374242e4b08ecf834fa82f !