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6x squared minus 5x equals four. how do you solve for 'x'?
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\[6x^2-5x=4\] ??
yes
use quadratic formula \[D= (-b \pm \sqrt{b^2-4ac})/2a\]
ok thank you
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yeah im checking it so far i got 1/2 and 4/3
cool
here b=-5, a=6, c=-4....now put these values
ok this time i got 1/2 and negative 4/3
cool..that's right
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yeah thank you :)
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