Question

Find the sum of n terms of series:
1/2 + 3/4 + 7/8 + 15/16 + ................

Answer 1

do you know the sum of n terms of series
1/2+1/4+1/8+1/16.....?

if so, how is that any different from 1-1/2+1-1/4+1-1/8...

Answer 2

\[ \sum_{n=1}^\infty {2^n-1 \over 2^n}\]
i guess you can do this

Answer 3

I want to solve it in AGP

Answer 4

i took 1/2 =x
but i am stuck

Answer 5

diverges!!

Answer 6

the former part diverges ... so the whole series diverges

Answer 7

not exactly sure what AGP is
but look at

1+1+1+1... for n terms

then look at
1/2+(1/2)^2+(1/2)^3+... for n terms

then
1-1/2= 1/2
1-(1/2)^2=1/4
...

does this help?

Answer 8

1-(1/2)^2=3/4*

Answer 9

is that up to n terms??

Answer 10

n - 1/2(1/(1 - 1/2)) = n - 1