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If 3X squared minus 2X +7 equals zero then what is X minus one third squared
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\[3x^2-2x-7=0\] can you solve this for x
3x^2-2x=-7
use \[D= \frac{ (-b \pm \sqrt b^2-4ac) }{ 2a }\]
Idk that
put b= -2, a=3, c=7
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