Question

Wonder full hard stuff plz help.

Answer 1

\[A=\frac{ 1 }{ 2}h(b1+b2)\]
Solve for h

Answer 2

(2A)/(b1+b2)=h

Answer 3

\[2*A=h(b1+b2)\] then \[h= (2*A)/(b1+b2)\]

Answer 4

ok is tht the answer?

Answer 5

yes

Answer 6

now solve for b2

Answer 7

(2A/h)-b1=b2

Answer 8

\[\frac{ 2A }{ h }= b1+b2\] then \[\frac{ 2A }{ h }-b1=b2\]

Answer 9

lol ok thnks thts the answer?

Answer 10

yes